을 찾는 채널 갈등에 의 이름을 불화 py
코드 예제
불 py 얻 채널 ID 여 이름
@bot.command()
async def get_channel(ctx, *, given_name=None):
for channel in ctx.guild.channels:
if channel.name == given_name:
wanted_channel_id = channel.id
await ctx.send(wanted_channel_id) # this is just to check
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