파이썬 목록에서 요소 제거
myList.remove(item) # Removes first instance of "item" from myList
myList.pop(i) # Removes and returns item at myList[i]
목록에서 항목 제거 파이썬
# removes item with given name in list
list = [15, 79, 709, "Back to your IDE"]
list.remove("Back to your IDE")
# removes last item in list
list.pop()
# pop() also works with an index...
list.pop(0)
# ...and returns also the "popped" item
item = list.pop()
목록 파이썬에서 값 삭제
list.remove(element)
값으로 파이썬 목록에서 값 제거
>>> a = ['a', 'b', 'c', 'd']
>>> a.remove('b')
>>> print a
['a', 'c', 'd']
파이썬 목록에서 요소를 제거하는 방법
# Basic syntax:
my_list.remove(element)
# Note, .remove(element) removes the first matching element it finds in
# the list.
# Example usage:
animals = ['cat', 'dog', 'rabbit', 'guinea pig', 'rabbit']
animals.remove('rabbit')
print(animals)
--> ['cat', 'dog', 'guinea pig', 'rabbit'] # Note only 1st instance of
# rabbit was removed from the list.
# Note, if you want to remove all instances of an element, convert the
# list to a set and back to a list, and then run .remove(element) E.g.:
animals = list(set['cat', 'dog', 'rabbit', 'guinea pig', 'rabbit']))
animals.remove('rabbit')
print(animals)
--> ['cat', 'dog', 'guinea pig']
목록 값에서 요소 삭제
>>> a=[1,2,3]
>>> a.remove(2)
>>> a
[1, 3]
>>> a=[1,2,3]
>>> del a[1]
>>> a
[1, 3]
>>> a= [1,2,3]
>>> a.pop(1)
2
>>> a
[1, 3]
>>>