문자열에 단어가 포함되어 있는지 php 확인
$myString = 'Hello Bob how are you?';
if (strpos($myString, 'Bob') !== false) {
echo "My string contains Bob";
}
문자열이 포함 된 경우 php chech
$a = 'How are you?';
if (strpos($a, 'are') !== false) {
echo 'true';
}
php 문자열 포함
$mystring = 'abc';
$findme = 'a';
$pos = strpos($mystring, $findme);
str_includes php
<?php
$string = 'The lazy fox jumped over the fence';
if (str_contains($string, '')) {
echo "Checking the existence of an empty string will always return true";
}
if (str_contains($string, 'lazy')) {
echo "The string 'lazy' was found in the string\n";
}
if (str_contains($string, 'Lazy')) {
echo 'The string "Lazy" was found in the string';
} else {
echo '"Lazy" was not found because the case does not match';
}
# Checking the existence of the empty string will always return true
# The string 'lazy' was found in the string
# "Lazy" was not found because the case does not match
문자열에 하위 문자열 php 가 포함되어 있는지 확인하십시오
$a = 'How are you?';
if (strpos($a, 'are') !== false) {
echo 'true';
}
strpos php
<?php
function g($string,$start,$end){
preg_match_all('/' . preg_quote($start, '/') . '(.*?)'. preg_quote($end, '/').'/i', $string, $m);
$out = array();
foreach($m[1] as $key => $value){
$type = explode('::',$value);
if(sizeof($type)>1){
if(!is_array($out[$type[0]]))
$out[$type[0]] = array();
$out[$type[0]][] = $type[1];
} else {
$out[] = $value;
}
}
return $out;
}
print_r(g('Sample text, [/text to extract/] Rest of sample text [/WEB::http://google.com/] bla bla bla. ','[/','/]'));
?>
results:
Array
(
[0] => text to extract
[WEB] => Array
(
[0] => http://google.com
)
)
Can be helpfull to custom parsing :)