Php str_contains
코드 예제
문자열에 단어가 포함되어 있는지 php 확인
$myString = 'Hello Bob how are you?';
if (strpos($myString, 'Bob') !== false) {
echo "My string contains Bob";
}php 의 strpos
<?php
$mystring = 'abc';
$findme = 'a';
$pos = strpos($mystring, $findme);
// Note our use of ===. Simply == would not work as expected
// because the position of 'a' was the 0th (first) character.
if ($pos === false) {
echo "The string '$findme' was not found in the string '$mystring'";
} else {
echo "The string '$findme' was found in the string '$mystring'";
echo " and exists at position $pos";
}
?>
하위 문자열이 문자열에있는 경우 php 찾기
$result = strpos("haystack", "needle");
if ($result != false)
{
// text found
}문자열에 php 에 하위 문자열이 포함되어 있는지 확인하는 방법
$a = 'How are you?';
if (strpos($a, 'are') !== false) {
echo 'true';
}
문자열이 포함되어 있는지 php 확인
// returns true if $needle is a substring of $haystack
function contains($haystack, $needle){
return strpos($haystack, $needle) !== false;
}str_includes php
<?php
$string = 'The lazy fox jumped over the fence';
if (str_contains($string, '')) {
echo "Checking the existence of an empty string will always return true";
}
if (str_contains($string, 'lazy')) {
echo "The string 'lazy' was found in the string\n";
}
if (str_contains($string, 'Lazy')) {
echo 'The string "Lazy" was found in the string';
} else {
echo '"Lazy" was not found because the case does not match';
}
# Checking the existence of the empty string will always return true
# The string 'lazy' was found in the string
# "Lazy" was not found because the case does not match비슷한 페이지
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